Linear Inequalities
Home/Class 11 Maths / Linear Inequalities
Linear Inequalities

Some Important Results

  1. If ‘k’ is a positive real number, then |x|  k   k  x  k, x  -k, k.


  1. If ‘k’ is a positive real number, then |x|  k   k  x  k, x  -k, k.


  1. If ‘k’ is a positive real number, then |x|  k  x  -k, x  k.


  1. If ‘k’ is a positive real number, then |x|  k  x  -k, x  k.


  1. If ‘k’ is a positive real number and ‘y’ is a fixed number, then

|x - y|  k  y  k  x  y + k, x  y -k, y + k.

  1. If ‘k’ is a positive real number and ‘y’ is a fixed number, then

|x - y|  k  y  k  x  y + k, x  [y -k, y + k].

  1. If ‘k’ is a positive real number and ‘y’ is a fixed number, then

|x - y|  k  x  y – k or x  y + k

  1. If ‘k’ be a positive real number and ‘y’ is a fixed number, then

|x - y|  k  x  y – k or x  y + k

  1. If a, b and c are positive real numbers, then a  |x|  b  x (-b, a)  (a, b)

  2. If a, b and c are positive real numbers, then a  |x|  b  x [-b, a]  (a, b)

  3. If a, b and c are positive real numbers, then a  |x - c|  b  x [-b + c, -a + c][a + c, b + c]

  4. If a, b and c are positive real numbers, then a  |x - c|  b  x (-b + c, -a + c)(a + c, b + c)

(Question 1)

Solve 30 x < 200 when x is a natural number.


(Question 2)

Solve 30 x < 200 when x is an integer.


(Question 3)

Solve 5x – 3 < 3x +1 when x is an integer.


(Question 4)

Solve 5x – 3 < 3x +1 when x is a real number.


(Question 5)

Solve 4x + 3 < 6x +7.


(Question 6)

Solve .


(Question 7)

Solve 7x + 3 < 5x + 9. Show the graph of the solutions on number line.


(Question 8)

Solve . Show the graph of the solutions on number line.


(Question 9)

The marks obtained by a student of Class XI in first and second terminal examination are 62 and 48, respectively. Find the minimum marks he should get in the annual examination to have an average of at least 60 marks.


(Question 10)

Find all pairs of consecutive odd natural numbers, both of which are larger than 10, such that their sum is less than 40.


(Question 11)

Solve – 8 5x – 3 < 7.


(Question 12)

Solve: - 5  8.


(Question 13)

Solve the system of inequalities:

  1. 3x – 7 < 5 + x
  2. 11 – 5 x 1

and represent the solutions on the number line.


(Question 14)

In an experiment, a solution of hydrochloric acid is to be kept between 30° and 35° Celsius. What is the range of temperature in degree Fahrenheit if conversion formula is given by C =  (F – 32), where C and F represent temperature in degree Celsius and degree Fahrenheit, respectively.


(Question 15)

A manufacturer has 600 litres of a 12% solution of acid. How many litres of a 30% acid solution must be added to it so that acid content in the resulting mixture will be more than 15% but less than 18%?


(Question 1)

Solve: 24x < 100, when x is a natural number.


(Question 2)

Solve: 24x < 100, when x is an integer.


(Question 3)

Solve – 12x > 30, when x is a natural number.


(Question 4)

Solve –12x > 30, when x is an integer.


(Question 5)

Solve: 5x – 3 < 7, when x is an integer.


(Question 6)

Solve: 5x – 3 < 7, when x is a real number.


(Question 7)

Solve 3x + 8 > 2, when x is an integer.


(Question 8)

Solve 3x + 8 > 2, when x is a real number.


(Question 9)

Solve the inequality 4x + 3 < 5x + 7 for real x.


(Question 10)

Solve the inequality 3x – 7 > 5x – 1 for real x.


(Question 11)

Solve the inequality 3(x – 1) 2 (x – 3) for real x.


(Question 12)

Solve the inequality 3 (2 – x) 2 (1 – x) for real x.


(Question 13)

Solve the inequality  for real x.


(Question 14)

Solve the inequality  for real x.


(Question 15)

Solve the inequality  for real x.


(Question 16)

Solve the inequality  for real x.


(Question 17)

Solve the inequality 2 (2x + 3) – 10 < 6 (x – 2) for real x.


(Question 18)

Solve the inequality 37 – (3x + 5) 9x – 8 (x – 3) for real x.


(Question 19)

Solve the inequality  for real x.


(Question 20)

Solve the inequality  for real x.


(Question 21)

Solve: 24x < 100, when x is a natural number.


(Question 22)

Solve: 24x < 100, when x is an integer.


(Question 23)

Solve – 12x > 30, when x is a natural number.


(Question 24)

Solve –12x > 30, when x is an integer.


(Question 25)

Solve: 5x – 3 < 7, when x is an integer.


(Question 26)

Solve: 5x – 3 < 7, when x is a real number.


(Question 27)

Solve 3x + 8 > 2, when x is an integer.


(Question 28)

Solve 3x + 8 > 2, when x is a real number.


(Question 29)

Solve the inequality 4x + 3 < 5x + 7 for real x.


(Question 30)

Solve the inequality 3x – 7 > 5x – 1 for real x.


(Question 31)

Solve the inequality 3(x – 1) 2 (x – 3) for real x.


(Question 32)

Solve the inequality 3 (2 – x) 2 (1 – x) for real x.


(Question 33)

Solve the inequality  for real x.


(Question 34)

Solve the inequality  for real x.


(Question 35)

Solve the inequality  for real x.


(Question 36)

Solve the inequality  for real x.


(Question 37)

Solve the inequality 2 (2x + 3) – 10 < 6 (x – 2) for real x.


(Question 38)

Solve the inequality 37 – (3x + 5) 9x – 8 (x – 3) for real x.


(Question 39)

Solve the inequality  for real x.


(Question 40)

Solve the inequality  for real x.


(Question 41)

Solve the inequality and show the graph for the solution on number line: 3x – 2 < 2x + 1


(Question 42)

Solve the inequality and show the graph for the solution on number line: 5x – 3 3x – 5


(Question 43)

Solve the inequality and show the graph for the solution on number line: 3 (1 – x) 2 (x + 4)


(Question 44)

Solve the inequality and show the graph for the solution on number line:


(Question 45)

Ravi obtained 70 and 75 marks in first two unit test. Find the minimum marks he should get in the third test to have an average of at least 60 marks.


(Question 46)

To receive Grade A, in a mathematics course, one must obtain an average of 90 marks or more in five examinations (each of 100 marks). If Ragini's marks in first four examinations are 87, 92, 94 and 95, find minimum marks that Ragini must obtain in fifth examination to get Grade A in the course.


(Question 47)

Find all pairs of consecutive odd positive integers both of which are smaller than 10 such that their sum is more than 11.


(Question 48)

Find all pairs of consecutive even positive integers, both of which are larger than 5 such that their sum is less than 23.


(Question 49)

The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm. Find the minimum length of the shortest side.


(Question 50)

A man wants to cut three lengths from a single piece of board of length 91 cm. The second length is to be 3 cm longer than the shortest and the third length is to be twice as long as the shortest. What are the possible lengths of the shortest board if the third piece is to be at least 5cm longer than the second?


(Question 1)

Solve the inequality: 2 3x – 4 5


(Question 2)

Solve the inequality:


(Question 3)

Solve the inequality: 


(Question 4)

Solve the inequality: 


(Question 5)

Solve the inequality: 


(Question 6)

Solve the inequality: 


(Question 7)

Solve the inequality and represent the solution graphically on number line: 5x + 1 > – 24, 5x – 1 < 24


(Question 8)

Solve the inequality and represent the solution graphically on number line: 2 (x – 1) x + 5, 3 (x + 2) 2 – x


(Question 9)

Solve the inequality and represent the solution graphically on number line: 3x – 7 2 (x – 6), 6 – x 11 – 2x


(Question 10)

Solve the inequality and represent the solution graphically on number line: 5 (2x – 7) – 3 (2x + 3) 0, 2x + 19 6x + 47.


(Question 11)

A solution is to be kept between 68°F and 77°F. What is the range in temperature in degree Celsius (C) if the Celsius / Fahrenheit (F) conversion formula is given by ?


(Question 12)

A solution of 8% boric acid is to be diluted by adding a 2% boric acid solution to it. The resulting mixture is to be more than 4% but less than 6% boric acid. If we have 640 litres of the 8% solution, how many litres of the 2% solution will have to be added?


(Question 13)

How many litres of water will have to be added to 1125 litres of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?


(Question 14)

IQ of a person is given by the formula

where MA is mental age and CA is chronological age. If 80 IQ 140 for a group of 12 years old children, find the range of their mental age.


Definitions

  1. Two real numbers or two algebraic expressions related by the symbol ‘<’, ‘>’, ‘≤’ or ‘≥’ form an inequality.

  2. Inequalities containing ‘<’, or ‘>’ are called strict inequalities.

  3. Inequalities containing ‘≤’ or ‘≥’ are called slack inequalities.

  4. An inequality containing any two of ‘<’, ‘>’, ‘≤’ or ‘≥’ is called double inequality.

  5. Solution an inequality in one variable is the value of the variable which makes it a true statement.

  6. Solving an inequality is the process of getting all possible solutions of an inequality.

  7. Solution set is the set of all possible solutions of an inequality is known as its solution set.

  8. A linear expression in one variable involving the inequality symbol is linear inequality in one variable.

General forms

ax + b < 0

ax + b > 0

ax + b ≤ 0

ax + b ≥ 0

  1. A linear inequality involving two variables is known as a linear inequality in two variables. General forms

ax + by < c

ax + by > c

ax + by ≤ c

ax + by ≥ c

  1. The following is the example of quadratic inequalities known as quadratic inequalities

ax² + bx + c ≤ 0

ax² + bx + c ≥ 0

  1. The inequalities of the form ‘<’ or ‘>’ are known as strict inequalities, whereas if they are of the form ≤ or ≥ then they are called slack inequalities.

  2. The region containing all the solutions of an inequality is called the solution region.

  3. The solution region of the system of inequalities is the region which satisfies all the given inequalities in the system simultaneously.

  4. Quadratic inequality is the quadratic polynomial with an inequality sign. Generic quadratic inequality is of the form ax2 + bx + c > 0.


Concepts

  1. If two real numbers are related by the symbols ‘<’, ‘>’, ‘≤’ or ‘≥’, then the inequality is a numerical inequality and in case of algebraic expressions it is literal inequality.

2<3 is numerical inequality.

5x + 2 ≤ 7 is literal inequality.


  1. Rules for simplifying the inequalities

Rule 1: Equal numbers may be added to (or subtracted from) both sides of an equation.

If a < b, then a + c < b + c.

Rule 2: Both sides of an equation may be multiplied (or divided) by the same non-zero number.

If a < b, then ac < bc

Rule 3: Sign of inequality is reversed in case of multiplication (or division) by a negative number.

If a < b, then ak > bk, where k is a negative number.

Rule 4: Sign of inequality is reversed in case of taking the reciprocals.


  1. A linear inequality can be solved by the following steps:

    1. Obtain the linear inequality.

    2. Group all variable terms on one side of the inequality and transpose the constant term on the other side of the inequality.

    3. Simplify both the sides of the inequality to the standard form

ax  b, or ax  b, or ax > b, or ax  b

    1. Solve the inequality by dividing both the sides of the inequality by the coefficient of the variable.

    2. Write and depict the solution set in the form of number line.


  1. Some examples of graphs of linear inequality: A linear inequality in one variable can be represented graphically as follows:Representation of x ï‚£ 1

Representation of x  1

Representation of x > 1

Steps to solve inequalities of the type,

  1. Step 1: Transpose all the variable terms on LHS.
  2. Step 2: Transpose all the variable terms on LHS.
  3. Step 3: Simplify the terms in LHS.
  4. Step 4: Make the coefficient of x positive in the numerator and denominator.
  5. Step 5: Equate both the numerator and denominator to zero and find the values of x and critical points.
  6. Step 6: Plot these critical points on the number line, which will divide the real line into three regions.
  7. Step 7: Mark the sign of the functions over the respective intervals.
  8. Step 8: Write solution regions in the form of intervals to get the required solution sets of the given inequality.
  1. A linear inequality in two variables represents a half plane geometrically. Types of half planes.





  1. In order to identify the half plane represented by an inequality, take any point (a, b) (not on line) and check whether it satisfies the inequality or not. If it satisfies the inequality, then the inequality represents the half plane and subsequently shades the region which contains the point; otherwise, the inequality represents the half plane which does not contain the point within it. For convenience, the point (0, 0) is preferred.


  1. If an inequality is of the type ax + b ≥ c or ax + b  c, i.e slack inequality, then the points on the line ax+ b = c are also included in the solution region.

Solution of slack inequality


  1. If an inequality is of the form ax + by > c or ax + by < c, then the points on the line ax + by = c are not to be included in the solution region.



Solution of strict inequality


  1. To represent x < a (or x > a) on a number line, put a circle on the number a and dark line to the left (or right) of the number a.


  1. To represent x ≤ a (or x ≥ a) on a number line, put a dark circle on the number a and dark line to the left (or right) of the number x.


  1. Steps to represent the linear inequality in two variables graphically


Step 1: Rewrite the inequality as linear equation, i.e. ax + by = c.

Step 2: Put x = 0 to get y-intercept of the line, i.e. (0, c/b).

Step 3: Put y = 0 to get x-intercept of the line, i.e. (c/a, 0).

Step 4: Join the two points, each on X-axis and Y-axis to get the graphical representation of the line.

Step5: Choose a point (x1, y1) in one of the planes, i.e. either to the left or right or upper or lower half of the line, but not on the line.

Step 6: If (x1, y1) satisfies the given inequality, then the required region is that particular half plane in which (x1, y1) lie.

On the other hand, if (x1, y1) does not satisfy the given inequality, then the required solution region is the half plane which does not contain (x1, y1).


  1. Linear inequalities represent regions; regions common to the given inequalities will be the solution region.

Similar to linear equations, there can be cases of overlapping of regions or no common regions for the given inequalities.


  1. To solve a system of inequalities graphically

  • Change the sign of equality to inequality and draw the graph of each line.

  • Shade the region for each inequality.

  • Common region to all the inequalities is the solution.


  1. A linear inequality divides the plane into two half planes, while a quadratic inequality is represented by a parabola which divides the plane into different regions.

Region represented by the inequality x2 + 5x + 6 > 0


  1. Interval Notations

Open Interval: The interval which contains all the elements between a and b excluding a and b. In set notations:

(a, b) = {x : a < x < b}



Closed interval: The interval which contains all the elements between a and b and also the end points a and b is called the closed interval.

[a, b] = {x : a ï‚£ x ï‚£ b}


Semi open intervals:


(a, b) = {x : a ï‚£ x < b} includes all the elements from a to b including a and excluding b.

[a, b] = {x : a < x ï‚£ b} includes all the elements from a to b excluding a and including b.



INTERVALS



1



A subset of number line is called an interval if it contains all the real numbers lying between every pair of its elements.

Let , then the set

(i) is called a closed interval and is denoted by [a, b].

(ii) is called an open interval and is denoted by (a, b), or ]a, b[.

(iii) is called left closed and right open interval and is denoted by [a, b) or [a, b[.

(iv) is called left open and right closed interval and is denoted by (a, b] or ]a, b].

(v) Discrete number are represented by curly { } brackets, e.g. {a, b}.


1.1 Number line

The extension of number line is from –¥ to +¥ and any real number can be represented on this number line.

The solution of the inequations are shown on this number line as illustrated in the following examples

Question: Solve x < 7 for the following cases

(a) x ÃŽ I (b) x ÃŽ N (c) x ÃŽ R

Solution: (a)

In this case

The infinite solutions are represented by dots

(b) x < 7,

In this case

The finite solutions are represented by dots.

(c) x < 7,

The infinite solutions are represented by a dark line as shown. A circle over 7 indicates that point 7 is not included in the solution.